The depth at which the effective value of acceleration due to gravity is $\frac{g}{4}$ is
The depth at which the effective value of acceleration due to gravity is $\frac{g}{4}$ is
$R$
$\frac{{3R}}{4}$
$\frac{{R}}{2}$
$\frac{R}{4}$
The depth at which the effective value of acceleration due to gravity is $\frac{g}{4}$ is
$g' = g\,\left( {1 - \frac{d}{R}} \right) \Rightarrow \frac{g}{4} = g\,\left( {1 - \frac{d}{R}} \right)\, \Rightarrow d = \frac{3}{4}R$
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