The average velocity of a body moving with uniform acceleration travelling a distance of $3.06\, m$ is $ 0.34 ms^{-1}$. If the change in velocity of the body is $ 0.18ms^{-1}$ during this time, its uniform acceleration is.........$ms^{-2}$
The average velocity of a body moving with uniform acceleration travelling a distance of $3.06\, m$ is $ 0.34 ms^{-1}$. If the change in velocity of the body is $ 0.18ms^{-1}$ during this time, its uniform acceleration is.........$ms^{-2}$
$0.01$
$0.02$
$0.03$
$0.04 $
The average velocity of a body moving with uniform acceleration travelling a distance of $3.06\, m$ is $ 0.34 ms^{-1}$. If the change in velocity of the body is $ 0.18ms^{-1}$ during this time, its uniform acceleration is.........$ms^{-2}$
${\rm{Time}} = \frac{{{\rm{Distance}}}}{{{\rm{Average\, velocity}}}} = \frac{{3.06}}{{0.34}} = 9\;\sec $
Acceleration$ = \frac{{{\rm{Change \,in \,velocity }}}}{{{\rm{Time }}}}$$ = \frac{{0.18}}{9}$ $=0.02$ $m/{s^2}$