The average force necessary to stop a bullet of mass $20\, g$ moving with a speed of $250 \,m/s$, as it penetrates into the wood for a distance of $12\, cm$ is
The average force necessary to stop a bullet of mass $20\, g$ moving with a speed of $250 \,m/s$, as it penetrates into the wood for a distance of $12\, cm$ is
$2.2 \times {10^3}N$
$3.2 \times {10^3}N$
$4.2 \times {10^3}N$
$5.2 \times {10^3}N$
The average force necessary to stop a bullet of mass $20\, g$ moving with a speed of $250 \,m/s$, as it penetrates into the wood for a distance of $12\, cm$ is
$u = 250\,m/s$, $v = 0$, $s = 0.12\,metre$
$F = ma = m\left( {\frac{{{u^2} - {v^2}}}{{2s}}} \right) = \frac{{20 \times {{10}^{ - 3}} \times {{(250)}^2}}}{{2 \times 0.12}}$
$\therefore F = 5.2 \times {10^3}\,N$
Other Language