The angle turned by a body undergoing circ

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The angle turned by a body undergoing circular motion depends on time as $\theta = {\theta _0} + {\theta _1}t + {\theta _2}{t^2}$. Then the angular acceleration of the body is

A

${\theta _1}$

B

${\theta _2}$

C

$2{\theta _1}$

D

$2{\theta _2}$

The angle turned by a body undergoing circular motion depends on time as $\theta = {\theta _0} + {\theta _1}t + {\theta _2}{t^2}$. Then the angular acceleration of the body is

Angular acceleration$ = \frac{{{d^2}\theta }}{{d{t^2}}}= 2\theta_2$