The angle of projection at which the horizontal range and maximum height of projectile are equal is
The angle of projection at which the horizontal range and maximum height of projectile are equal is
${45^o}$
$\theta = {\tan ^{ - 1}}(0.25)$
$\theta = {\tan ^{ - 1}}(4)$ or $\theta = 76^\circ $
${60^o}$
The angle of projection at which the horizontal range and maximum height of projectile are equal is
$R = 4H\cot \theta .$
When $R = H$ then $\cot \theta = 1/4$
$ \Rightarrow \theta = {\tan ^{ - 1}}(4)$
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