Starting from rest, acceleration of a particle is $a = 2(t - 1).$ The velocity of the particle at $t = 5\,s$ is.........$m/sec$
$15$
$25$
$5$
$3$
Starting from rest, acceleration of a particle is $a = 2(t - 1).$ The velocity of the particle at $t = 5\,s$ is.........$m/sec$
$ \Rightarrow dv = 2(t - 1)\;dt$
$ \Rightarrow \nu = \int_0^5 2 \;(t - 1)dt = 2\left[ {\frac{{{t^2}}}{2} - t} \right]_0^5$$ = 2\left[ {\frac{{25}}{2} - 5} \right]$ $ = 15 \,m/s$
Other Language