Potential energy of a satellite having mass $‘m’$ and rotating at a height of $6.4 \times {10^6}\,m$ from the earth surface is
$ - 0.5\,mg{R_e}$
$ - mg{R_e}$
$ - 2\,mg{R_e}$
$4\,mg{R_e}$
Potential energy of a satellite having mass $‘m’$ and rotating at a height of $6.4 \times {10^6}\,m$ from the earth surface is
Potential energy = $\frac{{ - GMm}}{r} $
$= \frac{{GMm}}{{{R_e} + h}} $
$= \frac{{ - GMm}}{{2{R_e}}}$
$= - \frac{{gR_e^2m}}{{2{R_e}}}$
$= - \frac{1}{2}mg{R_e}$
$ = - 0.5mg{R_e}$
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