$P, Q$ and $R$ are three coplanar forces acting at a point and are in equilibrium. Given $P = 1.9318 \,kg \,wt$, $\sin {\theta _1} = 0.9659$, the value of $R$ is ( in kg wt)
$0.9659$
$2$
$1$
$0.5$
$P, Q$ and $R$ are three coplanar forces acting at a point and are in equilibrium. Given $P = 1.9318 \,kg \,wt$, $\sin {\theta _1} = 0.9659$, the value of $R$ is ( in kg wt)
$\frac{P}{{\sin {\theta _1}}} = \frac{Q}{{\sin {\theta _2}}} = \frac{R}{{\sin \,\,150^\circ }}$
$ \Rightarrow \,\frac{{1.93}}{{\sin {\theta _1}}} = \frac{R}{{\sin \,150^\circ }}$
$ \Rightarrow \,R = \frac{{1.93 \times \sin \,150^\circ }}{{\sin {\theta _1}}} = \frac{{1.93 \times 0.5}}{{0.9659}} = 1$
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