One end of massless rope, which passes over a massless and frictionless pulley $P$ is tied to a hook while the other is free. Maximum tension the rope bear is $360 N$. With what value of maximum safe acceleration (in $m s^{-2}$) can a man of $60 kg$ climb on the rope?
One end of massless rope, which passes over a massless and frictionless pulley $P$ is tied to a hook while the other is free. Maximum tension the rope bear is $360 N$. With what value of maximum safe acceleration (in $m s^{-2}$) can a man of $60 kg$ climb on the rope?
$16$
$6$
$4$
$8$
One end of massless rope, which passes over a massless and frictionless pulley $P$ is tied to a hook while the other is free. Maximum tension the rope bear is $360 N$. With what value of maximum safe acceleration (in $m s^{-2}$) can a man of $60 kg$ climb on the rope?
Assuming acceleration $a$ of the man is downwards. So the equation will be
$m g-T=m a$
$\therefore a=g-\frac{T}{m}=10-\frac{360}{60}=4 m / s ^{2}$
So the maximum acceleration of man is $4 m / s ^{2}$ downwards.
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