On the horizontal surface of a truck a block of mass $1 \;kg$ is placed $(\mu=0.6)$ and truck is moving with acceleration $5\; m / sec ^2$ then the frictional force on the block will be
On the horizontal surface of a truck a block of mass $1 \;kg$ is placed $(\mu=0.6)$ and truck is moving with acceleration $5\; m / sec ^2$ then the frictional force on the block will be
$5$
$6$
$5.88$
$8$
On the horizontal surface of a truck a block of mass $1 \;kg$ is placed $(\mu=0.6)$ and truck is moving with acceleration $5\; m / sec ^2$ then the frictional force on the block will be
$$ ${F_l} = \mu mg = 0.6 \times 1 \times 9.8 = 5.88\;N$
Pseudo force on the block = $ma = 1 \times 5 = 5\;N$
Pseudo is less then limiting friction hence static force of friction $= 5\, N.$
Other Language