Mass of moon is $7.34 \times {10^{22}}\,kg$. If the acceleration due to gravity on the moon is $1.4\,m/{s^2}$, the radius of the moon is $(G = 6.667 \times {10^{ - 11}}\,N{m^2}/k{g^2})$
$0.56 \times {10^4}\,m$
$1.87 \times {10^6}\,m$
$1.92 \times {10^6}\,m$
$1.01 \times {10^8}\,m$
Mass of moon is $7.34 \times {10^{22}}\,kg$. If the acceleration due to gravity on the moon is $1.4\,m/{s^2}$, the radius of the moon is $(G = 6.667 \times {10^{ - 11}}\,N{m^2}/k{g^2})$
$g = \frac{{GM}}{{{R^2}}}$ $⇒$ $R = \sqrt {\frac{{GM}}{g}} $
Substituting the above values we get $R = 1.87 \times {10^6}m.$
Other Language