Mass of a person sitting in a lift is $50\, kg$. If lift is coming down with a constant acceleration of $10 \,m/se{c^2}.$ Then the reading of spring balance will be ......... $N$ $(g = 10m/se{c^2})$
Mass of a person sitting in a lift is $50\, kg$. If lift is coming down with a constant acceleration of $10 \,m/se{c^2}.$ Then the reading of spring balance will be ......... $N$ $(g = 10m/se{c^2})$
$0$
$1000$
$100$
$10$
Mass of a person sitting in a lift is $50\, kg$. If lift is coming down with a constant acceleration of $10 \,m/se{c^2}.$ Then the reading of spring balance will be ......... $N$ $(g = 10m/se{c^2})$
$R = m\,(g - a) = 0$