In an elevator moving vertically up with an acceleration $g$, the force exerted on the floor by a passenger of mass $M$ is
$Mg$
$\frac{1}{2}Mg$
$Zero$
$2\, Mg$
In an elevator moving vertically up with an acceleration $g$, the force exerted on the floor by a passenger of mass $M$ is
$R = \;m\;(g + a) = m\;(g + g) = 2mg$