If velocity of a body is twice of previous

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If velocity of a body is twice of previous velocity, then kinetic energy will become

A

$2 $ times

B

$\frac{1}{2}$times

C

$4$  times

D

$1 $ times

If velocity of a body is twice of previous velocity, then kinetic energy will become

Kinetic energy = $\frac{1}{2}m{v^2}$
K.E.$ \propto v_2$
If velocity is doubled then kinetic energy will become four times.