If time of flight of a projectile is $10$ seconds. Range is $500$ meters. The maximum height attained by it will be ......... $m$
$125 $
$50 $
$100 $
$150 $
If time of flight of a projectile is $10$ seconds. Range is $500$ meters. The maximum height attained by it will be ......... $m$
$T = \frac{{2u\sin \theta }}{g} = 10\sec \Rightarrow u\sin \theta = 50\;m/s$
$H = \frac{{{u^2}{{\sin }^2}\theta }}{{2g}} = \frac{{{{(u\sin \theta )}^2}}}{{2g}} = \frac{{50 \times 50}}{{2 \times 10}} = 125m$
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