If there is a positive error of $50\%$ in the measurement of velocity of a body, then the error in the measurement of kinetic energy is .............. $\%$
$25$
$50$
$100$
$125$
If there is a positive error of $50\%$ in the measurement of velocity of a body, then the error in the measurement of kinetic energy is .............. $\%$
Kinetic energy $E = \frac{1}{2}m{v^2}$
$\therefore \,\,\,\frac{{\Delta E}}{E} \times 100 = \frac{{{{v'}^2} - {v^2}}}{{{v^2}}} \times 100$
$ = [{(1.5)^2} - 1] \times 100$
$\therefore \,\,\frac{{\Delta E}}{E} \times 100 = 125\% $
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