If the radius of curvature of the path of two particles of same masses are in the ratio $1 : 2$, then in order to have constant centripetal force, their velocity, should be in the ratio of
If the radius of curvature of the path of two particles of same masses are in the ratio $1 : 2$, then in order to have constant centripetal force, their velocity, should be in the ratio of
$1:4$
$4:1$
$\sqrt 2:1$
$1\,\,:\,\,\sqrt 2 $
If the radius of curvature of the path of two particles of same masses are in the ratio $1 : 2$, then in order to have constant centripetal force, their velocity, should be in the ratio of
$$ The centripetal force, $F = \frac{{m{v^2}}}{r}$
$⇒$ $r = \frac{{m{v^2}}}{F}$
$⇒$ $r \propto {v^2}$ or $v \propto \sqrt r $ (If $m$ and $F$ are constant),
$⇒$ $\frac{{{v_1}}}{{{v_2}}} = \sqrt {\frac{{{r_1}}}{{{r_2}}}} = \sqrt {\frac{1}{2}} $