If the momentum of a body is increased by $100\%$, then the percentage increase in the kinetic energy is ............ $\%$
If the momentum of a body is increased by $100\%$, then the percentage increase in the kinetic energy is ............ $\%$
$150$
$200$
$225$
$300$
If the momentum of a body is increased by $100\%$, then the percentage increase in the kinetic energy is ............ $\%$
$E = \frac{{{P^2}}}{{2m}}$ ==> ${E_2} = {E_1}{\left( {\frac{{{P_2}}}{{{P_1}}}} \right)^2}$$ = {E_1}{\left( {\frac{{2P}}{P}} \right)^2}$
==> ${E_2} = 4E = E + 3E$$ = E + 300\% $ of $E$
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