If the length of rod $A$ is $3.25 \pm 0.01 \,cm$ and that of $B$ is $4.19 \pm 0.01\, cm $ then the rod $B$ is longer than rod $A$ by
If the length of rod $A$ is $3.25 \pm 0.01 \,cm$ and that of $B$ is $4.19 \pm 0.01\, cm $ then the rod $B$ is longer than rod $A$ by
$0.94 \pm 0.00 \,cm$
$0.94 \pm 0.01 \,cm$
$0.94 \pm 0.02 \,cm$
$0.94 \pm 0.005\, cm$
If the length of rod $A$ is $3.25 \pm 0.01 \,cm$ and that of $B$ is $4.19 \pm 0.01\, cm $ then the rod $B$ is longer than rod $A$ by
$x=(4.19 \pm 0.01)-(3.25 \pm 0.01)$
$x=(4.19-3.25) \pm(0.01+0.01)$
$x=0.94 \pm0.02$
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