If the increase in the kinetic energy of a body is $22\%$, then the increase in the momentum will be ........... $\%$
$22$
$44$
$10$
$300$
If the increase in the kinetic energy of a body is $22\%$, then the increase in the momentum will be ........... $\%$
$P = \sqrt {2mE} .$ If m is constant then
$\frac{{{P_2}}}{{{P_1}}} = \sqrt {\frac{{{E_2}}}{{{E_1}}}} = \sqrt {\frac{{1.22E}}{E}} $==> $\frac{{{P_2}}}{{{P_1}}} = \sqrt {1.22} = 1.1$
==>${P_2} = 1.1{P_1}$==> ${P_2} = {P_1} + 0.1{P_1} = {P_1} + 10\% \;{\rm{of }}\;{P_1}$
So the momentum will increase by $10\%$