If the equation for the displacement of a particle moving on a circular path is given by $(\theta ) = 2{t^3} + 0.5$, where $\theta $ is in radians and $t$ in seconds, then the angular velocity of the particle after $2 \,sec$ from its start is ......... $rad/sec$
If the equation for the displacement of a particle moving on a circular path is given by $(\theta ) = 2{t^3} + 0.5$, where $\theta $ is in radians and $t$ in seconds, then the angular velocity of the particle after $2 \,sec$ from its start is ......... $rad/sec$
$8$
$12$
$24$
$36$
If the equation for the displacement of a particle moving on a circular path is given by $(\theta ) = 2{t^3} + 0.5$, where $\theta $ is in radians and $t$ in seconds, then the angular velocity of the particle after $2 \,sec$ from its start is ......... $rad/sec$
$\omega = \frac{{d\theta }}{{dt}} = \frac{d}{{dt}}(2{t^3} + 0.5) = 6{t^2}$
at $t =2 \,s$, $\omega = 6 \times {(2)^2} = 24\,rad/s$
Other Language