If the acceleration due to gravity is $10\,m{s^{ - 2}}$ and the units of length and time are changed in kilometer and hour respectively, the numerical value of the acceleration is
If the acceleration due to gravity is $10\,m{s^{ - 2}}$ and the units of length and time are changed in kilometer and hour respectively, the numerical value of the acceleration is
$360000$
$72000$
$36000$
$129600$
If the acceleration due to gravity is $10\,m{s^{ - 2}}$ and the units of length and time are changed in kilometer and hour respectively, the numerical value of the acceleration is
${n_2} = {n_1}{\left[ {\frac{{{L_1}}}{{{L_2}}}} \right]^1}{\left[ {\frac{{{T_1}}}{{{T_2}}}} \right]^{ - 2}}$$ = 10{\left[ {\frac{{meter}}{{km}}} \right]^1}{\left[ {\frac{{\sec }}{{hr}}} \right]^{ - 2}}$
${n_2} = 10{\left[ {\frac{m}{{{{10}^3}m}}} \right]^1}{\left[ {\frac{{\sec }}{{3600\sec }}} \right]^{ - 2}}$$ = 129600$
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