If rope of lift breaks suddenly, the tension exerted by the surface of lift ($a =$ acceleration of lift)
If rope of lift breaks suddenly, the tension exerted by the surface of lift ($a =$ acceleration of lift)
$mg$
$m\,(g + a)$
$m(g - a)$
$0$
If rope of lift breaks suddenly, the tension exerted by the surface of lift ($a =$ acceleration of lift)
If rope of lift breaks suddenly, acceleration becomes equal to g so that tension, $T = m(g - g) = 0$