If radius of earth is $R$ then the height $‘h’ $ at which value of $‘g’ $ becomes one-fourth is
$\frac{R}{4}$
$\frac{{3R}}{4}$
$R$
$\frac{R}{8}$
If radius of earth is $R$ then the height $‘h’ $ at which value of $‘g’ $ becomes one-fourth is
$g' = g\,{\left( {\frac{R}{{R + h}}} \right)^2} = \frac{g}{4}$.
By solving $h = R$
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