If $R$ is the radius of the earth and $g$ the acceleration due to gravity on the earth's surface, the mean density of the earth is
If $R$ is the radius of the earth and $g$ the acceleration due to gravity on the earth's surface, the mean density of the earth is
$4\pi G/3gR$
$3\pi R/4gG$
$3g/4\pi RG$
$\pi RG/12G$
If $R$ is the radius of the earth and $g$ the acceleration due to gravity on the earth's surface, the mean density of the earth is
$g = \frac{{GM}}{{{R^2}}}$ and $M = \frac{4}{3}\pi {R^3} \times D $
$\therefore \,\,g = \frac{4}{3}\frac{{\pi {R^3} \times GD}}{{{R^2}}}\, \Rightarrow \,D = \frac{{3g.}}{{4\pi RG}}$
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