If in a stationary lift, a man is standing with a bucket full of water, having a hole at its bottom. The rate of flow of water through this hole is ${R_0}.$ If the lift starts to move up and down with same acceleration and then that rates of flow of water are ${R_u}$ and ${R_d},$ then
If in a stationary lift, a man is standing with a bucket full of water, having a hole at its bottom. The rate of flow of water through this hole is ${R_0}.$ If the lift starts to move up and down with same acceleration and then that rates of flow of water are ${R_u}$ and ${R_d},$ then
${R_0} > {R_u} > {R_d}$
${R_u} > {R_0} > {R_d}$
${R_d} > {R_0} > {R_u}$
${R_u} > {R_d} > {R_0}$
If in a stationary lift, a man is standing with a bucket full of water, having a hole at its bottom. The rate of flow of water through this hole is ${R_0}.$ If the lift starts to move up and down with same acceleration and then that rates of flow of water are ${R_u}$ and ${R_d},$ then
Rate of flow will be more when lift will move in upward direction with some acceleration because the net downward pull will be more and vice-versa.
${F_{{\rm{upward}}}} = m\,(g + a)$ and ${F_{{\rm{downward}}}} = m\,(g - a)$
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