If $g$ is the acceleration due to gravity on the earth’s surface, the gain in the potential energy of object of mass $m$ raised from the surface of the earth to a height equal to the radius $R$ of the earth is
If $g$ is the acceleration due to gravity on the earth’s surface, the gain in the potential energy of object of mass $m$ raised from the surface of the earth to a height equal to the radius $R$ of the earth is
$mgR$
$\frac{1}{2}mgR$
$2 mgR$
$\frac{1}{4}mgR$
If $g$ is the acceleration due to gravity on the earth’s surface, the gain in the potential energy of object of mass $m$ raised from the surface of the earth to a height equal to the radius $R$ of the earth is
$\Delta U = \frac{{mgh}}{{1 + \frac{h}{R}}} = \frac{1}{2}mgR\,\,(\,\,\,h = R)$
Other Language