If g is the acceleration due to gravity at the earth's surface and $r$ is the radius of the earth, the escape velocity for the body to escape out of earth's gravitational field is
If g is the acceleration due to gravity at the earth's surface and $r$ is the radius of the earth, the escape velocity for the body to escape out of earth's gravitational field is
$gr$
$\sqrt {2gr} $
$g/r$
$r/g$
If g is the acceleration due to gravity at the earth's surface and $r$ is the radius of the earth, the escape velocity for the body to escape out of earth's gravitational field is
$K E+P \cdot E=0$
$\frac{1}{2} m v^{2}-\frac{G M m}{R}=0$
$\frac{1}{2} m v^{2}=\frac{G M m}{R}$
$V=\sqrt{\frac{2 G M \times R}{R \times R}}$
$g=\frac{G M}{R^{2}}$
$v=\sqrt{2 gr}$
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