If a lighter body (mass ${M_1}$ and velocity ${V_1}$) and a heavier body (mass ${M_2}$ and velocity ${V_2}$) have the same kinetic energy, then
If a lighter body (mass ${M_1}$ and velocity ${V_1}$) and a heavier body (mass ${M_2}$ and velocity ${V_2}$) have the same kinetic energy, then
${M_2}{V_2} < {M_1}{V_1}$
${M_2}{V_2} = {M_1}{V_1}$
${M_2}{V_1} = {M_1}{V_2}$
${M_2}{V_2} > {M_1}{V_1}$
If a lighter body (mass ${M_1}$ and velocity ${V_1}$) and a heavier body (mass ${M_2}$ and velocity ${V_2}$) have the same kinetic energy, then
$P = \sqrt {2\,mE} .$If kinetic energy are equal then $P \propto \sqrt m $
i.e., heavier body posses large momentum
As ${M_1} < {M_2}$therefore ${M_1}{V_1} < {M_2}{V_2}$