If a cycle wheel of radius $4 \,m$ completes one revolution in two seconds. Then acceleration of a point on the cycle wheel will be
If a cycle wheel of radius $4 \,m$ completes one revolution in two seconds. Then acceleration of a point on the cycle wheel will be
${\pi ^2}m/{s^2}$
$2{\pi ^2}m/{s^2}$
$4{\pi ^2}m/{s^2}$
$8\pi \,m/{s^2}$
If a cycle wheel of radius $4 \,m$ completes one revolution in two seconds. Then acceleration of a point on the cycle wheel will be
Centripetal acceleration$ = 4{\pi ^2}{n^2}r = 4{\pi ^2}{\left( {\frac{1}{2}} \right)^2} \times 4 = 4{\pi ^2}$