If a body is in equilibrium under a set of non-collinear forces, then the minimum number of forces has to be
A
$4$
B
$3$
C
$2$
D
$5$
If a body is in equilibrium under a set of non-collinear forces, then the minimum number of forces has to be
since they are non collinear therefore there must be atleast three forces for body to be in equilibrium.
Example$-$ All three forces are equal with $120^{\circ}$ difference.
Therefore, $\mathrm{B}$ is correct option.