Gravels are dropped on a conveyor belt at the rate of $0.5\, kg/sec$. The extra force required in newtons to keep the belt moving at $2 \,m/sec$ is
Gravels are dropped on a conveyor belt at the rate of $0.5\, kg/sec$. The extra force required in newtons to keep the belt moving at $2 \,m/sec$ is
$1$
$2$
$4$
$0.5$
Gravels are dropped on a conveyor belt at the rate of $0.5\, kg/sec$. The extra force required in newtons to keep the belt moving at $2 \,m/sec$ is
Opposing force $F = u\;\left( {\frac{{dm}}{{dt}}} \right) = 2 \times 0.5 = 1\;N$ $\left( {{\rm{As,}}\;F = u\frac{{du}}{{dt}}} \right)$
So same amount of force is required to keep the belt moving at $2 \,m/s$