Given vector $\overrightarrow A = 2\hat i + 3\hat j, $ the angle between $\overrightarrow A $and $y-$axis is
${\tan ^{ - 1}}3/2$
${\tan ^{ - 1}}2/3$
${\sin ^{ - 1}}2/3$
${\cos ^{ - 1}}2/3$
Given vector $\overrightarrow A = 2\hat i + 3\hat j, $ the angle between $\overrightarrow A $and $y-$axis is
$\vec{A}=2 \hat{i}+3 \hat{j}$
$A=|\vec{A}|=\sqrt{4+9}=\sqrt{13}$
$\cos \beta=\frac{y}{A}=\frac{3}{\sqrt{13}}$
$\cos \beta=\frac{3}{\sqrt{13}}$
$\sin \beta=\frac{x}{A}=\frac{2}{\sqrt{13}}$
$\operatorname{Tan} \beta =\frac{x}{y}=\frac{2}{3}$
$=\tan ^{-1}\left(\frac{2}{3}\right)$
$A=|\vec{A}|=\sqrt{4+9}=\sqrt{13}$
$\cos \beta=\frac{y}{A}=\frac{3}{\sqrt{13}}$
$\cos \beta=\frac{3}{\sqrt{13}}$
$\sin \beta=\frac{x}{A}=\frac{2}{\sqrt{13}}$
$\operatorname{Tan} \beta =\frac{x}{y}=\frac{2}{3}$
$=\tan ^{-1}\left(\frac{2}{3}\right)$
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