From the top of a tower two stones, whose masses are in the ratio $1 :2$ are thrown one straight up with an initial speed $u$ and the second straight down with the same speed $u$. Then, neglecting air resistance
From the top of a tower two stones, whose masses are in the ratio $1 :2$ are thrown one straight up with an initial speed $u$ and the second straight down with the same speed $u$. Then, neglecting air resistance
The heavier stone hits the ground with a higher speed
The lighter stone hits the ground with a higher speed
Both the stones will have the same speed when they hit the ground.
The speed can't be determined with the given data.
From the top of a tower two stones, whose masses are in the ratio $1 :2$ are thrown one straight up with an initial speed $u$ and the second straight down with the same speed $u$. Then, neglecting air resistance
first stone thrown straight up with velocity $u$ upward and gravitation acceleration acts downwards.
so first particle goes up to some height when its velocity becomes zero and then this particle gets free fall. now when the particle goes down at level of top of tower it velocity becomes $u$ downward and gravitation acceleration also in downward direction.
by using newtons law of motion. for first particle
$v^2=u^2+2$ as $\quad(a=g ; s=h$ height of tower)
$v_1^2=u^2+2 g h$
same as for second particle
initial velocity is u downward and $g$ downward
$v^2=u^2+2$ as $\quad(a=g ; \quad s=h$ height of tower $)$
$v_2^2=u^2+2 g h$
So both the stones have same speed at the ground level hence option $C$ is correct