Distance of geostationary satellite from the surface of earth $radius\,\,({R_e} = 6400\,\,km)$ in terms of ${R_e}$ is .......
$13.76$
$10.76$
$6.56$
$2.56$
Distance of geostationary satellite from the surface of earth $radius\,\,({R_e} = 6400\,\,km)$ in terms of ${R_e}$ is .......
A geostationary satellite is placed at an altitude of about $36000 km$ from earth. surface.
so, its distance from centre of earth is $=h=(36000+R e)$ k.m.
$R_e=$ radius of earth $=6400 km$.
$\therefore h =\left(36000+R_e\right)\,km .$
$=(36000+6400)\,km.$
$=42400\,km$
Distance in terms of $Re$ is $=(6400 \times 6.6)\,km$.
$=6.6 Re _e$
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