At what distance from the centre of the earth, the value of acceleration due to gravity $g$ will be half that on the surface ($R =$ radius of earth)
At what distance from the centre of the earth, the value of acceleration due to gravity $g$ will be half that on the surface ($R =$ radius of earth)
$2\, R$
$R$
$0.414 \,R$
$1.414\, R$
At what distance from the centre of the earth, the value of acceleration due to gravity $g$ will be half that on the surface ($R =$ radius of earth)
$g' = g\,{\left( {\frac{R}{{R + h}}} \right)^2}\, \Rightarrow \,\frac{1}{{\sqrt 2 }} = \frac{R}{{R + h}}$
$⇒$ $R + h = \sqrt 2 \,R$ $ \Rightarrow \,h = (\sqrt 2 - 1)R = 0.414\,R$
$R+h=1.414 \,R$
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