An object is thrown along a direction inclined at an angle of ${45^o}$ with the horizontal direction. The horizontal range of the particle is equal to
An object is thrown along a direction inclined at an angle of ${45^o}$ with the horizontal direction. The horizontal range of the particle is equal to
Vertical height
Twice the vertical height
Thrice the vertical height
Four times the vertical height
An object is thrown along a direction inclined at an angle of ${45^o}$ with the horizontal direction. The horizontal range of the particle is equal to
$R = 4H\cot \theta $
if $\theta = 45^\circ $ then $R = 4H\cot (45^\circ ) = 4H$