An object is projected at an angle of $45^°$ with the horizontal. The horizontal range and the maximum height reached will be in the ratio.
$1:2$
$2:1$
$1:4$
$4:1$
An object is projected at an angle of $45^°$ with the horizontal. The horizontal range and the maximum height reached will be in the ratio.
$R = 4H\cot \theta ,$
If $\theta = 45^\circ$ then $R = 4H$
$⇒$ $\frac{R}{H} = \frac{4}{1}$