An aeroplane is moving with horizontal velocity $u$ at height $h$. The velocity of a packet dropped from it on the earth's surface will be ($g$ is acceleration due to gravity)
$\sqrt {{u^2} + 2gh} $
$\sqrt {2gh} $
$2gh$
$\sqrt {{u^2} - 2gh} $
An aeroplane is moving with horizontal velocity $u$ at height $h$. The velocity of a packet dropped from it on the earth's surface will be ($g$ is acceleration due to gravity)
Horizontal velocity of dropped packet $ = u$
Vertical velocity $ = \sqrt {2gh} $
$\therefore $ Resultant velocity at earth $ = \sqrt {{u^2} + 2gh} $
Vertical velocity $ = \sqrt {2gh} $
$\therefore $ Resultant velocity at earth $ = \sqrt {{u^2} + 2gh} $
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