An aeroplane is flying horizontally with a velocity of $600\, km/h$ at a height of $1960\, m$. When it is vertically at a point $A$ on the ground, a bomb is released from it. The bomb strikes the ground at point $B$. The distance $AB$ is
$1200 \,m$
$0.33\, km$
$3.33\, km$
$33 \,km$
An aeroplane is flying horizontally with a velocity of $600\, km/h$ at a height of $1960\, m$. When it is vertically at a point $A$ on the ground, a bomb is released from it. The bomb strikes the ground at point $B$. The distance $AB$ is
Horizontal displacement of the bomb
$AB$ = Horizontal velocity $×$ time available
$AB = \,u \times \sqrt {\frac{{2h}}{g}} $ $ = 600 \times \frac{5}{{18}} \times \sqrt {\frac{{2 \times 1960}}{{9.8}}} $ $ = 3.33\,Km.$
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