Acceleration due to gravity is$ ‘g’ $on the surface of the earth. The value of acceleration due to gravity at a height of $32\, km$ above earth’s surface is ........ $g$. (Radius of the earth$ = 6400 \,km$)
Acceleration due to gravity is$ ‘g’ $on the surface of the earth. The value of acceleration due to gravity at a height of $32\, km$ above earth’s surface is ........ $g$. (Radius of the earth$ = 6400 \,km$)
$0.9$
$0.99 $
$0.8$
$1.01$
Acceleration due to gravity is$ ‘g’ $on the surface of the earth. The value of acceleration due to gravity at a height of $32\, km$ above earth’s surface is ........ $g$. (Radius of the earth$ = 6400 \,km$)
$h = 32\,km$, $R = 6400\,km$, so $h < < R$
$g' = g\left( {1 - \frac{{2h}}{R}} \right)$ $ = g\left( {1 - \frac{{2 \times 32}}{{6400}}} \right)$
$⇒$ $g' = \frac{{99}}{{100}}g = 0.99\,g$
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