A vehicle of $100\, kg$ is moving with a velocity of $5 \,m/sec$. To stop it in $\frac{1}{{10}}\sec $, the required force in opposite direction is ........... $N$
$5000$
$500$
$50$
$1000$
A vehicle of $100\, kg$ is moving with a velocity of $5 \,m/sec$. To stop it in $\frac{1}{{10}}\sec $, the required force in opposite direction is ........... $N$
$F = m\;\left( {\frac{{dv}}{{dt}}} \right) = \frac{{100 \times 5}}{{0.1}} = 5000\;N$