A uniform chain of length $L$ and mass $M$ is lying on a smooth table and one third of its length is hanging vertically down over the edge of the table. If $g$ is acceleration due to gravity, the work required to pull the hanging part on to the table is
$MgL$
$MgL/3$
$MgL/9$
$MgL/18$
A uniform chain of length $L$ and mass $M$ is lying on a smooth table and one third of its length is hanging vertically down over the edge of the table. If $g$ is acceleration due to gravity, the work required to pull the hanging part on to the table is
$W = \frac{{MgL}}{{2{n^2}}} = \frac{{MgL}}{{2{{(3)}^2}}} = \frac{{MgL}}{{18}}$($n = 3$ given)
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