A tennis ball dropped from a height of $2 \,m$ rebounds only $1.5 \,m$ after hitting the ground. What fraction of its energy is lost in the impact
$\frac{1}{4}$
$\frac{1}{2}$
$\frac{1}{3}$
$\frac{1}{8}$
A tennis ball dropped from a height of $2 \,m$ rebounds only $1.5 \,m$ after hitting the ground. What fraction of its energy is lost in the impact
Fractional loss $ = \frac{{\Delta U}}{U} = \frac{{mg(h - h')}}{{mgh}}$$ = \frac{{2 - 1.5}}{2} = \frac{1}{4}$