A spring of force constant $800\, N/m$ has an extension of $5\,cm$. The work done in extending it from $ 5\,cm$ to $15 \,cm$ is ............. $\mathrm{J}$
A spring of force constant $800\, N/m$ has an extension of $5\,cm$. The work done in extending it from $ 5\,cm$ to $15 \,cm$ is ............. $\mathrm{J}$
$16$
$8$
$32$
$24$
A spring of force constant $800\, N/m$ has an extension of $5\,cm$. The work done in extending it from $ 5\,cm$ to $15 \,cm$ is ............. $\mathrm{J}$
$W = \frac{1}{2}k(x_2^2 - x_1^2) = \frac{1}{2} \times 800 \times ({15^2} - {5^2}) \times {10^{ - 4}}$$ = 8\,J$
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