A spring of force constant $10\, N/m$ has an initial stretch $0.20\, m.$ In changing the stretch to $0.25\, m$, the increase in potential energy is about.....$joule$
A spring of force constant $10\, N/m$ has an initial stretch $0.20\, m.$ In changing the stretch to $0.25\, m$, the increase in potential energy is about.....$joule$
$0.1$
$0.2$
$0.3$
$0.5$
A spring of force constant $10\, N/m$ has an initial stretch $0.20\, m.$ In changing the stretch to $0.25\, m$, the increase in potential energy is about.....$joule$
$\Delta$P.E.$ = \frac{1}{2}k(x_2^2 - x_1^2) = \frac{1}{2} \times 10[{(0.25)^2} - {(0.20)^2}]$
$ = 5 \times 0.45 \times 0.05 = 0.1\,J$
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