A rope of length $L$ is pulled by a constant force $F$. What is the tension in the rope at a distance $x$ from the end where the force is applied
A rope of length $L$ is pulled by a constant force $F$. What is the tension in the rope at a distance $x$ from the end where the force is applied
$\frac{{FL}}{x}$
$\frac{{F(L - x)}}{L}$
$\frac{{FL}}{{L - x}}$
$\frac{{Fx}}{{L - x}}$
A rope of length $L$ is pulled by a constant force $F$. What is the tension in the rope at a distance $x$ from the end where the force is applied
$a=\frac{F}{M}$
Mass per unit length $\lambda=\frac{M}{l}$
Hence mass of the part of length $(l-x)$ is given by $m=\lambda(l-x)$
$\Longrightarrow m=\frac{M(l-x)}{l}$
For this part$-$
$T=m a=\frac{M(l-x)}{l} \times \frac{F}{M}$
$\Longrightarrow T=\frac{F(l-x)}{l}$
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