A proton of mass $ 1.6 \times 10^{-27} kg$ goes round in a circular orbit of radius $0.10\, m$ under a centripetal force of $4 \times 10^{-13}\, N$. then the frequency of revolution of the proton is about
A proton of mass $ 1.6 \times 10^{-27} kg$ goes round in a circular orbit of radius $0.10\, m$ under a centripetal force of $4 \times 10^{-13}\, N$. then the frequency of revolution of the proton is about
$0.08 \times 10^8 $cycles per sec
$4 \times 10^8 $cycles per sec
$8 \times 10^8 $cycles per sec
$12 \times 10^8 $cycles per sec
A proton of mass $ 1.6 \times 10^{-27} kg$ goes round in a circular orbit of radius $0.10\, m$ under a centripetal force of $4 \times 10^{-13}\, N$. then the frequency of revolution of the proton is about
$m\,4{\pi ^2}{n^2}r = 4 \times {10^{ - 13}}$ $⇒$ $n = 0.08 \times {10^8}\,cycles/\sec .$