A projectile thrown with a speed $v$ at an angle $\theta $ has a range $R$ on the surface of earth. For same $v$ and $\theta $, its range on the surface of moon will be
A projectile thrown with a speed $v$ at an angle $\theta $ has a range $R$ on the surface of earth. For same $v$ and $\theta $, its range on the surface of moon will be
$R/6$
$6R$
$R/36$
$36R$
A projectile thrown with a speed $v$ at an angle $\theta $ has a range $R$ on the surface of earth. For same $v$ and $\theta $, its range on the surface of moon will be
Range is given by $R = \frac{{{u^2}\sin 2\theta }}{g}$
On moon ${g_m} = \frac{g}{6}$. Hence ${R_m} = 6R$
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