A position dependent force $F = 7 - 2x + 3{x^2}\,newton$ acts on a small body of mass $2\, kg$ and displaces it from $x = 0$ to $x = 5\,m$. The work done in joules is
A position dependent force $F = 7 - 2x + 3{x^2}\,newton$ acts on a small body of mass $2\, kg$ and displaces it from $x = 0$ to $x = 5\,m$. The work done in joules is
$70$
$270$
$35$
$135$
A position dependent force $F = 7 - 2x + 3{x^2}\,newton$ acts on a small body of mass $2\, kg$ and displaces it from $x = 0$ to $x = 5\,m$. The work done in joules is
$W = \int\limits_0^5 {Fdx} = \int\limits_0^5 {(7 - 2x + 3{x^2})\;dx} $
= ${[7x - {x^2} + {x^3}]^5_0}$
$= 35 -25 + 125 = 135 J$
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